2019-11-02 12:07:41 +08:00
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# 63. 股票的最大利润
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2019-11-03 23:57:08 +08:00
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## 题目链接
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2022-01-07 09:00:01 +00:00
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[Leetcode：121. Best Time to Buy and Sell Stock](https://leetcode.com/problems/best-time-to-buy-and-sell-stock/description/)
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2019-11-02 12:07:41 +08:00
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## 题目描述
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可以有一次买入和一次卖出，买入必须在前。求最大收益。
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2022-01-07 09:00:01 +00:00
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\
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2019-11-02 12:07:41 +08:00
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## 解题思路
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2020-11-05 01:34:00 +08:00
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使用贪心策略，假设第 i 轮进行卖出操作，买入操作价格应该在 i 之前并且价格最低。因此在遍历数组时记录当前最低的买入价格，并且尝试将每个位置都作为卖出价格，取收益最大的即可。
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2019-11-02 12:07:41 +08:00
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```java
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public int maxProfit(int[] prices) {
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if (prices == null || prices.length == 0)
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return 0;
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int soFarMin = prices[0];
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int maxProfit = 0;
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for (int i = 1; i < prices.length; i++) {
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soFarMin = Math.min(soFarMin, prices[i]);
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maxProfit = Math.max(maxProfit, prices[i] - soFarMin);
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}
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return maxProfit;
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}
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```
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