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notes/Leetcode 题解 - 搜索.md
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@ -32,7 +32,7 @@
# BFS
<div align="center"> <img src="pics/95903878-725b-4ed9-bded-bc4aae0792a9.jpg"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/95903878-725b-4ed9-bded-bc4aae0792a9.jpg"/> </div><br>
广度优先搜索一层一层地进行遍历，每层遍历都以上一层遍历的结果作为起点，遍历一个距离能访问到的所有节点。需要注意的是，遍历过的节点不能再次被遍历。
@ -269,7 +269,7 @@ private int getShortestPath(List<Integer>[] graphic, int start, int end) {
# DFS
<div align="center"> <img src="pics/74dc31eb-6baa-47ea-ab1c-d27a0ca35093.png"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/74dc31eb-6baa-47ea-ab1c-d27a0ca35093.png"/> </div><br>
广度优先搜索一层一层遍历，每一层得到的所有新节点，要用队列存储起来以备下一层遍历的时候再遍历。
@ -591,7 +591,7 @@ Backtracking（回溯）属于 DFS。
[Leetcode](https://leetcode.com/problems/letter-combinations-of-a-phone-number/description/) / [力扣](https://leetcode-cn.com/problems/letter-combinations-of-a-phone-number/description/)
<div align="center"> <img src="pics/9823768c-212b-4b1a-b69a-b3f59e07b977.jpg"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/9823768c-212b-4b1a-b69a-b3f59e07b977.jpg"/> </div><br>
```html
Input:Digit string "23"
@ -1194,7 +1194,7 @@ private boolean isPalindrome(String s, int begin, int end) {
[Leetcode](https://leetcode.com/problems/sudoku-solver/description/) / [力扣](https://leetcode-cn.com/problems/sudoku-solver/description/)
<div align="center"> <img src="pics/0e8fdc96-83c1-4798-9abe-45fc91d70b9d.png"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/0e8fdc96-83c1-4798-9abe-45fc91d70b9d.png"/> </div><br>
```java
private boolean[][] rowsUsed = new boolean[9][10];
@ -1253,7 +1253,7 @@ private int cubeNum(int i, int j) {
[Leetcode](https://leetcode.com/problems/n-queens/description/) / [力扣](https://leetcode-cn.com/problems/n-queens/description/)
<div align="center"> <img src="pics/067b310c-6877-40fe-9dcf-10654e737485.jpg"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/067b310c-6877-40fe-9dcf-10654e737485.jpg"/> </div><br>
在 n\*n 的矩阵中摆放 n 个皇后，并且每个皇后不能在同一行，同一列，同一对角线上，求所有的 n 皇后的解。
@ -1261,12 +1261,12 @@ private int cubeNum(int i, int j) {
45 度对角线标记数组的长度为 2 \* n - 1，通过下图可以明确 (r, c) 的位置所在的数组下标为 r + c。
<div align="center"> <img src="pics/9c422923-1447-4a3b-a4e1-97e663738187.jpg" width="300px"> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/9c422923-1447-4a3b-a4e1-97e663738187.jpg" width="300px"> </div><br>
135 度对角线标记数组的长度也是 2 \* n - 1，(r, c) 的位置所在的数组下标为 n - 1 - (r - c)。
<div align="center"> <img src="pics/7a85e285-e152-4116-b6dc-3fab27ba9437.jpg" width="300px"> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/7a85e285-e152-4116-b6dc-3fab27ba9437.jpg" width="300px"> </div><br>
```java
private List<List<String>> solutions;
@ -1320,4 +1320,4 @@ private void backtracking(int row) {
<div align="center"><img width="320px" src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/githubio/公众号二维码-1.png"></img></div>
<div align="center"><img width="320px" src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/githubio/公众号二维码-2.png"></img></div>