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docs/notes/剑指 Offer 题解 - 50~59.md
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@ -120,7 +120,7 @@ private void merge(int[] nums, int l, int m, int h) {
## 题目描述
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/5f1cb999-cb9a-4f6c-a0af-d90377295ab8.png" width="500"/> </div><br>
<div align="center"> <img src="pics/5f1cb999-cb9a-4f6c-a0af-d90377295ab8.png" width="500"/> </div><br>
## 解题思路
@ -212,7 +212,7 @@ private void inOrder(TreeNode root, int k) {
从根结点到叶结点依次经过的结点（含根、叶结点）形成树的一条路径，最长路径的长度为树的深度。
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/ba355101-4a93-4c71-94fb-1da83639727b.jpg" width="350px"/> </div><br>
<div align="center"> <img src="pics/ba355101-4a93-4c71-94fb-1da83639727b.jpg" width="350px"/> </div><br>
## 解题思路
@ -230,7 +230,7 @@ public int TreeDepth(TreeNode root) {
平衡二叉树左右子树高度差不超过 1。
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/af1d1166-63af-47b6-9aa3-2bf2bd37bd03.jpg" width="250px"/> </div><br>
<div align="center"> <img src="pics/af1d1166-63af-47b6-9aa3-2bf2bd37bd03.jpg" width="250px"/> </div><br>
## 解题思路