diff --git a/notes/Leetcode 题解.md b/notes/Leetcode 题解.md
index cfa4a59f..281bae0a 100644
--- a/notes/Leetcode 题解.md	
+++ b/notes/Leetcode 题解.md	
@@ -2544,23 +2544,31 @@ Given the above grid map, return 7. Because the path 1→3→1→1→1 minimizes
 
 ```java
 public int minPathSum(int[][] grid) {
-    if (grid.length == 0 || grid[0].length == 0) {
-        return 0;
-    }
-    int m = grid.length, n = grid[0].length;
-    int[] dp = new int[n];
-    for (int i = 0; i < m; i++) {
-        for (int j = 0; j < n; j++) {
-            if (i == 0) {
-                dp[j] = dp[j - 1];
-            } else {
-                dp[j] = Math.min(dp[j - 1], dp[j]);
-            }
-            dp[j] += grid[i][j];
+        if (grid.length==0 || grid[0].length == 0) {
+            return 0;
         }
+        int m = grid.length, n = grid[0].length;
+        int[] dp = new int[n];        
+        for(int i =0;i<m;i++) {
+            for(int j=0;j<n;j++){
+                if(i==0) {
+                    if(j==0) {
+                        dp[j] = grid[i][j];
+                    }
+                    else {
+                    dp[j]=dp[j-1] + grid[i][j];
+                    }
+                }else if(j==0) {
+                    dp[j] = dp[j] + grid[i][j];
+                }
+                else{
+                dp[j] = Math.min(dp[j],dp[j-1])+grid[i][j];
+                }
+            }
+        }
+        
+        return dp[n-1];
     }
-    return dp[n - 1];
-}
 ```
 
 **矩阵的总路径数**