diff --git a/docs/notes/69. 股票的最大利润二.md b/docs/notes/69. 股票的最大利润二.md
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-# 69. 股票的最大利润 二
-
-## 题目链接
-
-[Leetcode：Best Time to Buy and Sell Stock II](https://leetcode.com/explore/interview/card/top-interview-questions-easy/92/array/564/)
-
-## 题目描述
-
-可以有任意次数买入和卖出，求最大收益。
-
-```html
-输入: [7,1,5,3,6,4]
-输出: 7
-解释：
-  - 第二天以1的价格买入，第三天以5的价格卖出.利润就是 5-1 = 4.
-  - 第四天以3的价格买入，第五天以6的价格卖出.利润就是 6-3 = 3.
-  - 所以总共利润就是4+3 = 7.
-```
-
-## 解题思路
-
-使用峰谷策略
-
-TODO: 添加图片 notes/pics/maxprofit2.png
-
-```java
-public int maxProfit(int[] prices) {
-    int i = 0;
-    int valley = prices[0];
-    int peak = prices[0];
-    int maxprofit = 0;
-    while (i < prices.length - 1) {
-        while (i < prices.length - 1 && prices[i] >= prices[i + 1])
-            i++;
-        valley = prices[i];
-        while (i < prices.length - 1 && prices[i] <= prices[i + 1])
-            i++;
-        peak = prices[i];
-        maxprofit += peak - valley;
-    }
-    return maxprofit;
-}
-```
-
-
-
-
-
-
-<div align="center"><img width="320px" src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/githubio/公众号二维码-2.png"></img></div>
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