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# 汉诺塔
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# 算法 - 其它
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## 汉诺塔
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/69d6c38d-1dec-4f72-ae60-60dbc10e9d15.png" width="300"/> </div><br>
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这是一个经典的递归问题,分为三步求解:
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① 将 n-1 个圆盘从 from -> buffer
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① 将 n-1 个圆盘从 from -\> buffer
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/f9240aa1-8d48-4959-b28a-7ca45c3e4d91.png" width="300"/> </div><br>
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② 将 1 个圆盘从 from -> to
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② 将 1 个圆盘从 from -\> to
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/f579cab0-3d49-4d00-8e14-e9e1669d0f9f.png" width="300"/> </div><br>
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③ 将 n-1 个圆盘从 buffer -> to
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③ 将 n-1 个圆盘从 buffer -\> to
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/d02f74dd-8e33-4f3c-bf29-53203a06695a.png" width="300"/> </div><br>
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@ -50,7 +51,7 @@ from H2 to H3
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from H1 to H3
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```
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# 哈夫曼编码
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## 哈夫曼编码
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根据数据出现的频率对数据进行编码,从而压缩原始数据。
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@ -126,10 +127,3 @@ public class Huffman {
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}
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}
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```
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<div align="center"><img width="320px" src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/githubio/公众号二维码-2.png"></img></div>
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