diff --git a/notes/剑指 offer 题解.md b/notes/剑指 offer 题解.md
index 7fdef7de..10976409 100644
--- a/notes/剑指 offer 题解.md
+++ b/notes/剑指 offer 题解.md
@@ -1040,7 +1040,7 @@ public ListNode ReverseList(ListNode head) {
## 题目描述
- 
+ 
## 解题思路
@@ -1400,21 +1400,21 @@ private void dfs(TreeNode node, int target, ArrayList path) {
输入一个复杂链表（每个节点中有节点值，以及两个指针，一个指向下一个节点，另一个特殊指针指向任意一个节点），返回结果为复制后复杂链表的 head。
-
+
## 解题思路
第一步，在每个节点的后面插入复制的节点。
-
+
第二步，对复制节点的 random 链接进行赋值。
-
+
第三步，拆分。
-
+
```java
public RandomListNode Clone(RandomListNode pHead) {
@@ -1456,7 +1456,7 @@ public RandomListNode Clone(RandomListNode pHead) {
输入一棵二叉搜索树，将该二叉搜索树转换成一个排序的双向链表。要求不能创建任何新的结点，只能调整树中结点指针的指向。
-
+
## 解题思路
@@ -2046,13 +2046,7 @@ private void merge(int[] nums, int first, int mid, int last) {
## 题目描述
-```html
-A: a1 → a2
- ↘
- c1 → c2 → c3
- ↗
-B: b1 → b2 → b3
-```
+
## 解题思路
@@ -2148,6 +2142,8 @@ private void inOrder(TreeNode root, int k) {
从根结点到叶结点依次经过的结点（含根、叶结点）形成树的一条路径，最长路径的长度为树的深度。
+
+
## 解题思路
```java
@@ -2161,10 +2157,10 @@ public int TreeDepth(TreeNode root) {
## 题目描述
-
-
平衡二叉树左右子树高度差不超过 1。
+
+
## 解题思路
```java
@@ -2559,18 +2555,11 @@ public int StrToInt(String str) {
# 68. 树中两个节点的最低公共祖先
-## 二叉查找树
+## 解题思路
-```html
- _______6______
- / \
- ___2__ ___8__
- / \ / \
- 0 4 7 9
- / \
- 3 5
-For example, the lowest common ancestor (LCA) of nodes 2 and 8 is 6. Another example is LCA of nodes 2 and 4 is 2, since a node can be a descendant of itself according to the LCA definition.
-```
+### 二叉查找树
+
+
```java
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
@@ -2580,18 +2569,9 @@ public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
}
```
-## 普通二叉树
+### 普通二叉树
-```html
- _______3______
- / \
- ___5__ ___1__
- / \ / \
- 6 2 0 8
- / \
- 7 4
-For example, the lowest common ancestor (LCA) of nodes 5 and 1 is 3. Another example is LCA of nodes 5 and 4 is 5, since a node can be a descendant of itself according to the LCA definition.
-```
+
```java
public TreeNode lowestCommonAncestor(TreeNode root, TreeNode p, TreeNode q) {
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