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代码优化，去除剑指offer10.1题斐波那契数列最后一种解法中fib[2]=2的一行代码

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Vongkong 2019-04-14 11:44:31 +08:00
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docs/notes/剑指 Offer 题解 - 10~19.md
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@ -107,7 +107,6 @@ public class Solution {
public Solution() { public Solution() {
fib[1] = 1; fib[1] = 1;
fib[2] = 2;
for (int i = 2; i < fib.length; i++) for (int i = 2; i < fib.length; i++)
fib[i] = fib[i - 1] + fib[i - 2]; fib[i] = fib[i - 1] + fib[i - 2];
} }