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<!-- GFM-TOC -->
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* [20. 表示数值的字符串](#20-表示数值的字符串)
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* [21. 调整数组顺序使奇数位于偶数前面](#21-调整数组顺序使奇数位于偶数前面)
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* [22. 链表中倒数第 K 个结点](#22-链表中倒数第-k-个结点)
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* [23. 链表中环的入口结点](#23-链表中环的入口结点)
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* [24. 反转链表](#24-反转链表)
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* [25. 合并两个排序的链表](#25-合并两个排序的链表)
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* [26. 树的子结构](#26-树的子结构)
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* [27. 二叉树的镜像](#27-二叉树的镜像)
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* [28 对称的二叉树](#28-对称的二叉树)
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* [29. 顺时针打印矩阵](#29-顺时针打印矩阵)
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<!-- GFM-TOC -->
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[TOC]
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# 20. 表示数值的字符串
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@ -70,7 +58,7 @@ public boolean isNumeric(char[] str) {
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需要保证奇数和奇数,偶数和偶数之间的相对位置不变,这和书本不太一样。
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/d03a2efa-ef19-4c96-97e8-ff61df8061d3.png" width="200px"> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/d03a2efa-ef19-4c96-97e8-ff61df8061d3.png" width="200px">
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## 解题思路
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@ -131,7 +119,7 @@ private void swap(int[] nums, int i, int j) {
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设链表的长度为 N。设置两个指针 P1 和 P2,先让 P1 移动 K 个节点,则还有 N - K 个节点可以移动。此时让 P1 和 P2 同时移动,可以知道当 P1 移动到链表结尾时,P2 移动到第 N - K 个节点处,该位置就是倒数第 K 个节点。
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/6b504f1f-bf76-4aab-a146-a9c7a58c2029.png" width="500"/> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/6b504f1f-bf76-4aab-a146-a9c7a58c2029.png" width="500"/>
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```java
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public ListNode FindKthToTail(ListNode head, int k) {
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@ -165,7 +153,7 @@ public ListNode FindKthToTail(ListNode head, int k) {
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在相遇点,slow 要到环的入口点还需要移动 z 个节点,如果让 fast 重新从头开始移动,并且速度变为每次移动一个节点,那么它到环入口点还需要移动 x 个节点。在上面已经推导出 x=z,因此 fast 和 slow 将在环入口点相遇。
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/bb7fc182-98c2-4860-8ea3-630e27a5f29f.png" width="500"/> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/bb7fc182-98c2-4860-8ea3-630e27a5f29f.png" width="500"/>
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```java
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public ListNode EntryNodeOfLoop(ListNode pHead) {
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@ -228,7 +216,7 @@ public ListNode ReverseList(ListNode head) {
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## 题目描述
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/c094d2bc-ec75-444b-af77-d369dfb6b3b4.png" width="400"/> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/c094d2bc-ec75-444b-af77-d369dfb6b3b4.png" width="400"/>
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## 解题思路
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@ -280,7 +268,7 @@ public ListNode Merge(ListNode list1, ListNode list2) {
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## 题目描述
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/84a5b15a-86c5-4d8e-9439-d9fd5a4699a1.jpg" width="450"/> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/84a5b15a-86c5-4d8e-9439-d9fd5a4699a1.jpg" width="450"/>
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## 解题思路
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@ -308,7 +296,7 @@ private boolean isSubtreeWithRoot(TreeNode root1, TreeNode root2) {
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## 题目描述
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/0c12221f-729e-4c22-b0ba-0dfc909f8adf.jpg" width="300"/> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/0c12221f-729e-4c22-b0ba-0dfc909f8adf.jpg" width="300"/>
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## 解题思路
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@ -334,7 +322,7 @@ private void swap(TreeNode root) {
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## 题目描述
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/0c12221f-729e-4c22-b0ba-0dfc909f8adf.jpg" width="300"/> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/0c12221f-729e-4c22-b0ba-0dfc909f8adf.jpg" width="300"/>
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## 解题思路
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@ -364,7 +352,7 @@ boolean isSymmetrical(TreeNode t1, TreeNode t2) {
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下图的矩阵顺时针打印结果为:1, 2, 3, 4, 8, 12, 16, 15, 14, 13, 9, 5, 6, 7, 11, 10
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<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/48517227-324c-4664-bd26-a2d2cffe2bfe.png" width="200px"> </div><br>
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<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/48517227-324c-4664-bd26-a2d2cffe2bfe.png" width="200px">
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## 解题思路
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@ -388,10 +376,3 @@ public ArrayList<Integer> printMatrix(int[][] matrix) {
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return ret;
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}
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```
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<div align="center"><img width="320px" src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/githubio/公众号二维码-1.png"></img></div>
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