auto commit
This commit is contained in:
29
docs/notes/31. 栈的压入、弹出序列.md
Normal file
29
docs/notes/31. 栈的压入、弹出序列.md
Normal file
@ -0,0 +1,29 @@
|
||||
# 31. 栈的压入、弹出序列
|
||||
|
||||
[NowCoder](https://www.nowcoder.com/practice/d77d11405cc7470d82554cb392585106?tpId=13&tqId=11174&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
|
||||
|
||||
## 题目描述
|
||||
|
||||
输入两个整数序列,第一个序列表示栈的压入顺序,请判断第二个序列是否为该栈的弹出顺序。假设压入栈的所有数字均不相等。
|
||||
|
||||
例如序列 1,2,3,4,5 是某栈的压入顺序,序列 4,5,3,2,1 是该压栈序列对应的一个弹出序列,但 4,3,5,1,2 就不可能是该压栈序列的弹出序列。
|
||||
|
||||
## 解题思路
|
||||
|
||||
使用一个栈来模拟压入弹出操作。
|
||||
|
||||
```java
|
||||
public boolean IsPopOrder(int[] pushSequence, int[] popSequence) {
|
||||
int n = pushSequence.length;
|
||||
Stack<Integer> stack = new Stack<>();
|
||||
for (int pushIndex = 0, popIndex = 0; pushIndex < n; pushIndex++) {
|
||||
stack.push(pushSequence[pushIndex]);
|
||||
while (popIndex < n && !stack.isEmpty()
|
||||
&& stack.peek() == popSequence[popIndex]) {
|
||||
stack.pop();
|
||||
popIndex++;
|
||||
}
|
||||
}
|
||||
return stack.isEmpty();
|
||||
}
|
||||
```
|
Reference in New Issue
Block a user