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# 36. 二叉搜索树与双向链表
[NowCoder](https://www.nowcoder.com/practice/947f6eb80d944a84850b0538bf0ec3a5?tpId=13&tqId=11179&tPage=1&rp=1&ru=/ta/coding-interviews&qru=/ta/coding-interviews/question-ranking&from=cyc_github)
## 题目描述
输入一棵二叉搜索树将该二叉搜索树转换成一个排序的双向链表要求不能创建任何新的结点只能调整树中结点指针的指向
<img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/05a08f2e-9914-4a77-92ef-aebeaecf4f66.jpg" width="400"/>
## 解题思路
```java
private TreeNode pre = null;
private TreeNode head = null;
public TreeNode Convert(TreeNode root) {
inOrder(root);
return head;
}
private void inOrder(TreeNode node) {
if (node == null)
return;
inOrder(node.left);
node.left = pre;
if (pre != null)
pre.right = node;
pre = node;
if (head == null)
head = node;
inOrder(node.right);
}
```