Update 11. 旋转数组的最小数字.md
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```java
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public int minNumberInRotateArray(int[] nums) {
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if (nums.length == 0)
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if (nums.length == 0)//check the base case and ensure the array is not empty
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return 0;
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int l = 0, h = nums.length - 1;
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while (l < h) {
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while (l < h) {//iterate whille the middle is less than the length of the arry
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int m = l + (h - l) / 2;
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if (nums[m] <= nums[h])
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if (nums[m] <= nums[h])//switch at point where array elements ge equal
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h = m;
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else
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l = m + 1;
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