更新拼多多
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@ -1,4 +1,4 @@
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package com.raorao.interview.beike.t1;
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package com.raorao.interview.beike;
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import java.util.Arrays;
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import java.util.Comparator;
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package com.raorao.interview.beike.t1.t2;
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package com.raorao.interview.beike.t2;
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import java.util.Scanner;
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package com.raorao.interview.beike.t1.t3;
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package com.raorao.interview.beike.t3;
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import java.util.HashMap;
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import java.util.Map;
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package com.raorao.interview.bytedance;
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import java.util.ArrayList;
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import java.util.HashMap;
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import java.util.LinkedList;
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import java.util.Vector;
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/**
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* .
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*
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@ -8,4 +13,9 @@ package com.raorao.interview.bytedance;
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*/
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public class Test {
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public static void main(String[] args) {
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ArrayList a;
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LinkedList b;
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Vector v;
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}
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}
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package com.raorao.leetcode.q406;
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import java.util.ArrayList;
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import java.util.Arrays;
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import java.util.List;
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/**
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* 根据身高和序号重组队列.
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*
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* 题目描述:一个学生用两个分量 (h, k) 描述,h 表示身高,k 表示排在前面的有 k 个学生的身高比他高或者和他一样高。\
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*
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* 思路:贪心算法,为了在每次插入操作时不影响后续的操作,身高较高的学生应该先做插入操作,否则身高较小的学生原先正确插入第 k 个位置可能会变成第 k+1 个位置。
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*
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* 身高降序、k 值升序,然后按排好序的顺序插入队列的第 k 个位置中。
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*
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* @author Xiong Raorao
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* @since 2018-08-17-15:22
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*/
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public class Solution {
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public static void main(String[] args) {
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int[][] input = new int[][] {{7, 0}, {4, 4}, {7, 1}, {5, 0}, {6, 1}, {5, 2}};
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}
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public int[][] reconstructQueue(int[][] people) {
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return null;
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public static int[][] reconstructQueue(int[][] people) {
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if (people == null || people.length == 0 || people[0].length == 0) {
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return new int[0][0];
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}
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Arrays.sort(people, (a, b) -> a[0] == b[0] ? a[1] - b[1] : b[0] - a[0]); //升序排列就是小的放前面,大的放后面;
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List<int[]> queue = new ArrayList<>();
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for (int[] p : people) {
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queue.add(p[1], p);
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}
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return queue.toArray(new int[queue.size()][]);
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}
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}
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