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2019-05-02 23:30:42 +08:00
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docs/notes/剑指 Offer 题解 - 3~9.md
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@ -300,11 +300,11 @@ public class TreeLinkNode {
① 如果一个节点的右子树不为空，那么该节点的下一个节点是右子树的最左节点；
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/_u4E8C_u53C9_u6811_u7684_u4E0B_.gif" width="250"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/b0611f89-1e5f-4494-a795-3544bf65042a.gif" width="220px"/> </div><br>
② 否则，向上找第一个左链接指向的树包含该节点的祖先节点。
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/_u4E8C_u53C9_u6811_u7684_u4E0B_1548504426508.gif" width="250"/> </div><br>
<div align="center"> <img src="https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/95080fae-de40-463d-a76e-783a0c677fec.gif" width="200px"/> </div><br>
```java
public TreeLinkNode GetNext(TreeLinkNode pNode) {