# 55.2 平衡二叉树 [NowCoder](https://www.nowcoder.com/practice/8b3b95850edb4115918ecebdf1b4d222?tpId=13\&tqId=11192\&tPage=1\&rp=1\&ru=/ta/coding-interviews\&qru=/ta/coding-interviews/question-ranking\&from=cyc\_github) ## 题目描述 平衡二叉树左右子树高度差不超过 1。 ![](https://cs-notes-1256109796.cos.ap-guangzhou.myqcloud.com/af1d1166-63af-47b6-9aa3-2bf2bd37bd03.jpg)\ ## 解题思路 ```java private boolean isBalanced = true; public boolean IsBalanced_Solution(TreeNode root) { height(root); return isBalanced; } private int height(TreeNode root) { if (root == null || !isBalanced) return 0; int left = height(root.left); int right = height(root.right); if (Math.abs(left - right) > 1) isBalanced = false; return 1 + Math.max(left, right); } ```